1樓:
月線:=c#month;
月線多頭:count(月線》(月線,5) and (月線,5)>(月線,10) and (月線,10)>(月線,20),3);
能不能做乙個**多頭排列的選股公式?
2樓:匿名使用者
多頭bai排列
duzhi:ma(c,5)>ma(c,10) and ma(c,10)>ma(c,20) and ma(c,20)>ma(c,60)
and ma(c,60)>ma(c,120) and ma(c,120)>ref(ma(c,120),1) and ma(c,5)>ref(ma(c,5),1);
3樓:耀云
老實說,這個抄多頭排列的選股效襲果不一定好的!
bai我這裡推薦du乙個 顧比復合移動平均zhi線的多頭排列的選股公dao式吧。
k1:=ema(c,3);
k2:=ema(c,5);
k3:=ema(c,8) ;
k4:=ema(c,10);
k5:=ema(c,12) ;
k6:=ema(c,15);
k7:=ema(c,30);
k8:=ema(c,35) ;
k9:=ema(c,40);
k10:=ema(c,45);
k11:=ema(c,50);
k12:=ema(c,60);
k1>k2 and k2>k3 and k3>k4 and k4>k5 and k5>k6 and k6>k7 and k7>k8 and k8>k9 and k9>k10 and k10>k11 and k11>k12;
4樓:匿名使用者
a1:=ma(close,5);
a2:=ma(close,10);
a3:=ma(close,20);
a4:=ma(close,60);
a5:=ma(close,120);
多頭12345:= a1> a2 and a2 >a3 and a3> a4 and a4> a5 ;
5樓:臨窗聽聽聽雨
可以呀。ma(c,5)>ma(c,10) and ma(c,10)>>ma(c,20) and ma(c,20>>ma(c,60)
and ma(c,60)>>ma(c,120) and ma(c,120)>ref(ma(c,120),1) and ma(c,5)>ref(ma(c,5),1); ;
6樓:興斐雷傲菡
ma5:=ma(c,5);
ma10:=ma(c,10);
ma20:=ma(c,20);
ma40:=ma(c,40);
condtion_a:=ma5>ma10
andma10>ma20
andma20>ma40;
condtion_b:=(o-ma5)/ma5*100>=-1;
xg:condtion_a
andcondtion_b;
求乙個通達信選股公式,要求:**多頭排列 **角度大於0
7樓:醉笑天地
a1:=ma(close,5);
a2:=ma(close,10);
a3:=ma(close,20);
a4:=ma(close,30);
a5:=ma(close,60);
close>a1 and a1>a2 and a2>a3 and a3>a4 and a4>a5 and close>open and
a1>ref(a1,1) and a2>ref(a2,1) and a3>ref(a3,1) and a4>ref(a4,1) and a5>ref(a5,1);
求通達信**粘合首次出現多頭排列選股公式
8樓:般若若愚
xg:cross(((abs(ma(c,5)-ma(c,10))+abs(ma(c,10)-ma(c,20))+abs(ma(c,5)-ma(c,60))+abs(ma(c,10)-ma(c,60))+abs(ma(c,20)-ma(c,60))+abs(ma(c,5)-ma(c,20)))/c<0.09 andma(c,5)>ref(ma(c,5),1) andma(c,10)>ref(ma(c,10),1) andma(c,20)>ref(ma(c,20),1)andma(c,60)>ref(ma(c,60),1)),0.5);
請高手寫乙個通達信選股公式: 周線下**多頭排列,日線下5日**上穿10**。兩個條件同時進行!
9樓:
zc:=c#week;
zm5:=ma(zc,5);
zm10:=ma(zc,10);
ztd:=zm5>ref(zm5,1) and zm10>ref(zm10,1);
zxg:cross(ma(c,5),ma(c,10)) and ztd;
按你講述形態已寫出公式,如果達到你的要求請及時採納,多謝!
10樓:連有服
我麼注意的角度不同,導致看法不同啊7671
11樓:
你可以選擇條件相與來實現
求通達信裡面五,十。二十**多頭排列,macd,kdj金叉的選股公式
12樓:匿名使用者
ma(c,5)>ma(c,10) and ma(c,10)>ma(c,20) and ma(c,5)>ref(ma(c,5),1) and ma(c,10)>ref(ma(c,10),1) and ma(c,20)>ref(ma(c,20),1) and "macd.dif">"macd.dea" and "kdj.
j">"kdj.k" and "kdj.k">"kdj.d";
13樓:般若若愚
ma5:=ma(close,5);
ma10:=ma(close,10);
ma20:=ma(close,20);
dif:=ema(close,12)-ema(close,26);
dea:=ema(dif,9);
aa:=cross(dif,dea);
rsv:=(close-llv(low,9))/(hhv(high,9)-llv(low,9))*100;
k:=sma(rsv,3,1);
d:=sma(k,3,1);
j:=3*k-2*d;
bb:=cross(j,k);
xg:ma5>ma10 and ma10>ma20 and aa and bb;
ma5:=ma(close,5);
ma10:=ma(close,10);
ma20:=ma(close,20);
xg:ma5>ma10 and ma10>ma20 and cross( "macd.dif ","macd.
dea") and cross("kdj.j","kdj.k") ;
14樓:匿名使用者
今天太晚了,明天上午寫吧
15樓:q號
這麼好的公式不跟分,誰給你做呢?
16樓:匿名使用者
一大喬,二小喬,三寸金蓮四寸腰,五匣六盒七彩紛,八分九分十信嬌。(求下聯)答案:上聯:
一大喬,二小喬,三寸金蓮四寸腰,五匣六盒七彩紛,八分九分十信嬌。下聯:十九月,八分圓,七個進士六個還,五更四鼓三聲向,二喬大喬一人佔。
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