求S 1 2 3100VB程式設計過程

時間 2021-10-17 04:59:00

1樓:匿名使用者

因為不知道你所寫的**,所以僅僅將vb中「累加」**呈上即可:

dim i as integer, sum as integersum = 0

『使用迴圈將1至100累加到變數sum中

for i = 1 to 100

sum = sum + i

next i

print "s=1+2+3+...+100=" & sum

2樓:匿名使用者

public class form1

private sub button1_click(byval sender as system.object, byval e as system.eventargs) handles button1.

click

dim i as integer, s as integerfor i = 1 to 100

s = s + i

next

textbox1.text = s.tostringend sub

end class

3樓:匿名使用者

private sub command1_click()sum = 0

for i = 1 to 100

sum = sum + i

next i

print sum

end sub

這是我覺得最簡單的了,你應該會學會的,加油

vb程式設計計算:1+2!+3!+...+10!

4樓:匿名使用者

private sub command1_click()dim i as integer, j as integerdim l as long, h as longfor i = 1 to 10

h = 1

for j = 1 to i

h = h * j

next

l = l + h

next

print l

end sub

5樓:岔路程式緣

private sub form_click()

form1.autoredraw = true

me.show

dim sum as long, i as integer, j as integer

sum = 0

for i = 1 to 10

sum = sum + jc(i)

next

print "s=1+2!+3!+...+10!="; sum

end sub

private function jc(x as integer) as long

if x = 1 then jc = 1 else jc = x * jc(x - 1)

end function

或(do while loop ):

private sub form_click()

form1.autoredraw = true

me.show

dim sum as long, i as integer, j as integer

sum = 0

i=1do while i <= 10

sum = sum + jc(i)

i=i+1

loop

print "s=1+2!+3!+...+10!="; sum

end sub

private function jc(x as integer) as long

if x = 1 then jc = 1 else jc = x * jc(x - 1)

end function

6樓:亓靖瀅

dim i as integer

dim sum as integer

dim n as integer

n = 1

sum = 0

for i = 1 to 10

n = n * i

sum = sum + n

next

print(sum)

7樓:宿思敏羿宣

vb程式設計計算2+2^1+2^2+2^3+......+2^10private

subcommand1_click()

dimi%,s%s

=2fori=1

to10s=

s+2^

inext

iprint

send

subvb程式設計求出100-200以內的同時能被3和5整除的所有整數private

subcommand1_click()

dimi

asinteger

fori

=100

to200ifi

mod3=0

andi

mod5=0

then

print

i;end

ifnext

iend

subvb程式設計計算1-2+3-4+5-6……+-n,其中n由文字框輸入

private

subcommand1_click()

dimi%,

k%,s%k=

1fori=

1toval(text1.text)s=

s+i*

kk=-k

next

iprint

sendsub

vb程式設計,求1!+2!+3!+…+20!。謝謝!

8樓:匿名使用者

第乙個文字框(要求填入多少由你決定)

for i = 1 to text1.textb = b +i

next i

text2.text= b

將結果輸出到文字框二

9樓:鬱渟

sub test()

dim i as integer, x as double, y as double

x = 1

y = 0

for i = 1 to 20

x = x * i

y = y + x

next

msgbox y

end sub

10樓:牛人影視

privae sub command1_click()dim i as integer,s as longfor i=1 to 20

s=s+jc(i)

next i

msgbox s

end sub

private function jc(x as integer) as long

dim i as integer

jc=1

for i=1 to x

jc=jc*i

next i

end function

11樓:匿名使用者

n=20

s=0j=1

for i= 1 to n

j=j*i

s=s+j

next

msgbox s

12樓:匿名使用者

樓下的 回答 都挺好的.. 就是靠迴圈哦~~

用vb 編寫程式,計算1+2+3……+100的和。

13樓:匿名使用者

private sub form_load()dim i,s as integer

s=0for i=1 to 100

s=s+i

next i

print s

end sub

14樓:匿名使用者

dim i as integer, sum as integersum = 0

for i = 1 to 100

sum = sum + i

next i

print sum

編寫程式,計算s=1+2+3+……100的整數之和 20

15樓:匿名使用者

源**如下:

#include

#include

void main()

printf("整數之和是:%d\n", sum);

getchar();

}執行結果如下圖:

16樓:守望海之依賴

int i = 0,sum = 0;

for( i=1;i<=100;i++ )

17樓:匿名使用者

private static void main(string args)

console.writeline("1加到100的和為: "+sum);}

vb程式設計計算1+2+3+4……+100的值

18樓:紅山人

private sub form_click()dim s as integer

for i = 1 to 100

s = s + i

next i

print "1+2+....+100="; send sub

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